🟡 剑指 Offer 56 - I. 数组中数字出现的次数
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题目难度 中等
原题链接 🔗 leetcode
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题解 1_抄的.py# 用到的位运算公式:a异或a=0 0异或a=a # a异或b≠0 用来分组# https://leetcode-cn.com/problems/shu-zu-zhong-shu-zi-chu-xian-de-ci-shu-lcof/solution/jian-zhi-offer-56-i-shu-zu-zhong-shu-zi-tykom/class Solution: def singleNumbers(self, nums: List[int]) -> List[int]: xy, m = 0, 1 for num in nums: xy ^= num while m & xy == 0: m <<= 1 x, y = 0, 0 for num in nums: if num & m: x ^= num else: y ^= num return [x, y]